The winning New York Win 4 numbers for December 24, 2003 were: midday 6-5-5-4; evening 6-5-7-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 24, 2003 | Evening | 6-5-7-8 | 26 | 8 |
| Dec 24, 2003 | Midday | 6-5-5-4 | 20 | 2 |
| Dec 23, 2003 | Evening | 3-3-3-1 | 10 | 1 |
| Dec 23, 2003 | Midday | 5-3-2-3 | 13 | 4 |
| Dec 22, 2003 | Evening | 2-0-2-5 | 9 | 9 |
| Dec 22, 2003 | Midday | 0-0-0-7 | 7 | 7 |
| Dec 21, 2003 | Evening | 8-8-3-4 | 23 | 5 |
| Dec 21, 2003 | Midday | 9-6-0-9 | 24 | 6 |
| Dec 20, 2003 | Evening | 8-7-3-9 | 27 | 9 |
| Dec 20, 2003 | Midday | 4-3-0-4 | 11 | 2 |
| Dec 19, 2003 | Evening | 3-5-0-5 | 13 | 4 |
| Dec 19, 2003 | Midday | 6-7-5-2 | 20 | 2 |
| Dec 18, 2003 | Evening | 1-4-0-4 | 9 | 9 |
| Dec 18, 2003 | Midday | 2-4-1-9 | 16 | 7 |