The winning New York Win 4 numbers for December 17, 2003 were: midday 5-2-2-8; evening 0-5-5-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 17, 2003 | Evening | 0-5-5-7 | 17 | 8 |
| Dec 17, 2003 | Midday | 5-2-2-8 | 17 | 8 |
| Dec 16, 2003 | Evening | 6-5-8-2 | 21 | 3 |
| Dec 16, 2003 | Midday | 5-8-6-2 | 21 | 3 |
| Dec 15, 2003 | Evening | 3-1-2-8 | 14 | 5 |
| Dec 15, 2003 | Midday | 9-2-1-6 | 18 | 9 |
| Dec 14, 2003 | Evening | 6-3-9-7 | 25 | 7 |
| Dec 14, 2003 | Midday | 6-3-2-8 | 19 | 1 |
| Dec 13, 2003 | Evening | 8-9-3-0 | 20 | 2 |
| Dec 13, 2003 | Midday | 4-2-9-8 | 23 | 5 |
| Dec 12, 2003 | Evening | 3-1-8-7 | 19 | 1 |
| Dec 12, 2003 | Midday | 1-0-1-1 | 3 | 3 |
| Dec 11, 2003 | Evening | 9-9-1-8 | 27 | 9 |
| Dec 11, 2003 | Midday | 6-8-4-4 | 22 | 4 |