The winning New York Win 4 numbers for December 12, 2003 were: midday 1-0-1-1; evening 3-1-8-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 12, 2003 | Evening | 3-1-8-7 | 19 | 1 |
| Dec 12, 2003 | Midday | 1-0-1-1 | 3 | 3 |
| Dec 11, 2003 | Evening | 9-9-1-8 | 27 | 9 |
| Dec 11, 2003 | Midday | 6-8-4-4 | 22 | 4 |
| Dec 10, 2003 | Evening | 3-4-6-8 | 21 | 3 |
| Dec 10, 2003 | Midday | 2-9-2-1 | 14 | 5 |
| Dec 9, 2003 | Evening | 6-7-1-6 | 20 | 2 |
| Dec 9, 2003 | Midday | 9-0-5-9 | 23 | 5 |
| Dec 8, 2003 | Evening | 5-2-7-0 | 14 | 5 |
| Dec 8, 2003 | Midday | 6-9-3-8 | 26 | 8 |
| Dec 7, 2003 | Evening | 2-5-9-8 | 24 | 6 |
| Dec 7, 2003 | Midday | 1-8-5-5 | 19 | 1 |
| Dec 6, 2003 | Evening | 0-6-7-4 | 17 | 8 |
| Dec 6, 2003 | Midday | 6-4-3-5 | 18 | 9 |