The winning New York Win 4 numbers for December 29, 1993 were: evening 5-9-5-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 29, 1993 | Evening | 5-9-5-8 | 27 | 9 |
| Dec 28, 1993 | Evening | 1-3-9-7 | 20 | 2 |
| Dec 27, 1993 | Evening | 0-0-9-4 | 13 | 4 |
| Dec 26, 1993 | Evening | 8-4-7-0 | 19 | 1 |
| Dec 24, 1993 | Evening | 6-5-7-5 | 23 | 5 |
| Dec 23, 1993 | Evening | 4-5-8-4 | 21 | 3 |