The winning New York Win 4 numbers for October 5, 1993 were: evening 4-1-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 5, 1993 | Evening | 4-1-4-9 | 18 | 9 |
| Oct 4, 1993 | Evening | 2-6-5-4 | 17 | 8 |
| Oct 3, 1993 | Evening | 1-2-9-3 | 15 | 6 |
| Oct 2, 1993 | Evening | 3-6-0-9 | 18 | 9 |
| Oct 1, 1993 | Evening | 2-0-9-0 | 11 | 2 |
| Sep 30, 1993 | Evening | 0-0-0-6 | 6 | 6 |
| Sep 29, 1993 | Evening | 8-8-4-1 | 21 | 3 |