The winning New York Numbers numbers for December 4, 2003 were: midday 3-4-1; evening 5-4-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 4, 2003 | Evening | 5-4-6 | 15 | 6 |
| Dec 4, 2003 | Midday | 3-4-1 | 8 | 8 |
| Dec 3, 2003 | Evening | 8-1-3 | 12 | 3 |
| Dec 3, 2003 | Midday | 5-9-4 | 18 | 9 |
| Dec 2, 2003 | Evening | 7-2-6 | 15 | 6 |
| Dec 2, 2003 | Midday | 2-6-9 | 17 | 8 |
| Dec 1, 2003 | Evening | 0-8-6 | 14 | 5 |
| Dec 1, 2003 | Midday | 0-3-7 | 10 | 1 |
| Nov 30, 2003 | Evening | 9-9-8 | 26 | 8 |
| Nov 30, 2003 | Midday | 0-1-1 | 2 | 2 |
| Nov 29, 2003 | Evening | 2-4-2 | 8 | 8 |
| Nov 29, 2003 | Midday | 3-7-1 | 11 | 2 |
| Nov 28, 2003 | Evening | 1-2-9 | 12 | 3 |
| Nov 28, 2003 | Midday | 0-7-3 | 10 | 1 |