The winning New York Numbers numbers for September 27, 2003 were: midday 3-9-8; evening 9-0-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 27, 2003 | Evening | 9-0-2 | 11 | 2 |
| Sep 27, 2003 | Midday | 3-9-8 | 20 | 2 |
| Sep 26, 2003 | Evening | 6-8-1 | 15 | 6 |
| Sep 26, 2003 | Midday | 6-5-1 | 12 | 3 |
| Sep 25, 2003 | Evening | 3-1-9 | 13 | 4 |
| Sep 25, 2003 | Midday | 8-7-4 | 19 | 1 |
| Sep 24, 2003 | Evening | 3-2-9 | 14 | 5 |
| Sep 24, 2003 | Midday | 7-5-1 | 13 | 4 |
| Sep 23, 2003 | Evening | 2-5-4 | 11 | 2 |
| Sep 23, 2003 | Midday | 5-2-7 | 14 | 5 |
| Sep 22, 2003 | Evening | 4-9-5 | 18 | 9 |
| Sep 22, 2003 | Midday | 4-4-3 | 11 | 2 |
| Sep 21, 2003 | Evening | 4-3-5 | 12 | 3 |
| Sep 21, 2003 | Midday | 5-0-0 | 5 | 5 |