The winning New York Numbers numbers for July 24, 2003 were: midday 4-2-1; evening 3-8-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 24, 2003 | Evening | 3-8-9 | 20 | 2 |
| Jul 24, 2003 | Midday | 4-2-1 | 7 | 7 |
| Jul 23, 2003 | Evening | 7-8-7 | 22 | 4 |
| Jul 23, 2003 | Midday | 3-9-0 | 12 | 3 |
| Jul 22, 2003 | Evening | 3-5-4 | 12 | 3 |
| Jul 22, 2003 | Midday | 6-6-0 | 12 | 3 |
| Jul 21, 2003 | Evening | 5-8-3 | 16 | 7 |
| Jul 21, 2003 | Midday | 9-7-2 | 18 | 9 |
| Jul 20, 2003 | Evening | 4-8-2 | 14 | 5 |
| Jul 20, 2003 | Midday | 7-4-6 | 17 | 8 |
| Jul 19, 2003 | Evening | 9-1-0 | 10 | 1 |
| Jul 19, 2003 | Midday | 8-8-0 | 16 | 7 |
| Jul 18, 2003 | Evening | 2-6-4 | 12 | 3 |
| Jul 18, 2003 | Midday | 9-4-6 | 19 | 1 |