The winning New York Numbers numbers for December 29, 2002 were: midday 5-5-0; evening 5-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 29, 2002 | Evening | 5-5-0 | 10 | 1 |
| Dec 29, 2002 | Midday | 5-5-0 | 10 | 1 |
| Dec 28, 2002 | Evening | 6-5-6 | 17 | 8 |
| Dec 28, 2002 | Midday | 0-4-1 | 5 | 5 |
| Dec 27, 2002 | Evening | 8-8-5 | 21 | 3 |
| Dec 27, 2002 | Midday | 5-9-1 | 15 | 6 |
| Dec 26, 2002 | Evening | 6-0-2 | 8 | 8 |
| Dec 26, 2002 | Midday | 9-1-8 | 18 | 9 |
| Dec 24, 2002 | Evening | 0-5-6 | 11 | 2 |
| Dec 24, 2002 | Midday | 2-7-0 | 9 | 9 |
| Dec 23, 2002 | Evening | 8-6-1 | 15 | 6 |
| Dec 23, 2002 | Midday | 1-8-6 | 15 | 6 |