The winning New York Numbers numbers for November 28, 1999 were: evening 5-3-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 28, 1999 | Evening | 5-3-1 | 9 | 9 |
| Nov 27, 1999 | Evening | 4-2-6 | 12 | 3 |
| Nov 26, 1999 | Evening | 8-5-8 | 21 | 3 |
| Nov 25, 1999 | Evening | 6-5-2 | 13 | 4 |
| Nov 24, 1999 | Evening | 6-5-6 | 17 | 8 |
| Nov 23, 1999 | Evening | 5-9-1 | 15 | 6 |
| Nov 22, 1999 | Evening | 5-6-9 | 20 | 2 |