The winning New York Numbers numbers for November 9, 1999 were: evening 3-2-8.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 9, 1999 | Evening | 3-2-8 | 13 | 4 |
| Nov 8, 1999 | Evening | 2-0-0 | 2 | 2 |
| Nov 7, 1999 | Evening | 0-1-9 | 10 | 1 |
| Nov 6, 1999 | Evening | 0-4-8 | 12 | 3 |
| Nov 5, 1999 | Evening | 0-8-3 | 11 | 2 |
| Nov 4, 1999 | Evening | 7-8-1 | 16 | 7 |
| Nov 3, 1999 | Evening | 7-2-7 | 16 | 7 |