The winning New York Numbers numbers for September 25, 1999 were: evening 0-7-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 25, 1999 | Evening | 0-7-4 | 11 | 2 |
| Sep 24, 1999 | Evening | 4-4-7 | 15 | 6 |
| Sep 23, 1999 | Evening | 7-0-1 | 8 | 8 |
| Sep 22, 1999 | Evening | 4-2-1 | 7 | 7 |
| Sep 21, 1999 | Evening | 9-2-1 | 12 | 3 |
| Sep 20, 1999 | Evening | 8-3-7 | 18 | 9 |
| Sep 19, 1999 | Evening | 3-3-2 | 8 | 8 |