The winning New York Numbers numbers for March 19, 1999 were: evening 5-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 19, 1999 | Evening | 5-9-0 | 14 | 5 |
| Mar 18, 1999 | Evening | 9-3-9 | 21 | 3 |
| Mar 17, 1999 | Evening | 8-5-8 | 21 | 3 |
| Mar 16, 1999 | Evening | 9-5-7 | 21 | 3 |
| Mar 15, 1999 | Evening | 6-5-5 | 16 | 7 |
| Mar 14, 1999 | Evening | 3-8-2 | 13 | 4 |
| Mar 13, 1999 | Evening | 3-8-3 | 14 | 5 |