The winning New York Numbers numbers for March 2, 1999 were: evening 5-5-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 2, 1999 | Evening | 5-5-0 | 10 | 1 |
| Mar 1, 1999 | Evening | 9-6-8 | 23 | 5 |
| Feb 28, 1999 | Evening | 4-1-0 | 5 | 5 |
| Feb 27, 1999 | Evening | 4-8-7 | 19 | 1 |
| Feb 26, 1999 | Evening | 1-5-5 | 11 | 2 |
| Feb 25, 1999 | Evening | 0-9-1 | 10 | 1 |
| Feb 24, 1999 | Evening | 8-4-2 | 14 | 5 |