The winning New York Numbers numbers for December 26, 1998 were: evening 4-2-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 26, 1998 | Evening | 4-2-7 | 13 | 4 |
| Dec 24, 1998 | Evening | 0-6-5 | 11 | 2 |
| Dec 23, 1998 | Evening | 6-0-0 | 6 | 6 |
| Dec 22, 1998 | Evening | 8-0-6 | 14 | 5 |
| Dec 21, 1998 | Evening | 3-2-6 | 11 | 2 |
| Dec 20, 1998 | Evening | 4-3-6 | 13 | 4 |