The winning New York Numbers numbers for October 1, 1997 were: evening 8-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 1, 1997 | Evening | 8-1-0 | 9 | 9 |
| Sep 30, 1997 | Evening | 2-3-4 | 9 | 9 |
| Sep 29, 1997 | Evening | 9-3-3 | 15 | 6 |
| Sep 28, 1997 | Evening | 3-0-3 | 6 | 6 |
| Sep 27, 1997 | Evening | 9-0-7 | 16 | 7 |
| Sep 26, 1997 | Evening | 1-1-3 | 5 | 5 |
| Sep 25, 1997 | Evening | 2-3-9 | 14 | 5 |