The winning New York Numbers numbers for March 31, 1995 were: evening 9-2-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 31, 1995 | Evening | 9-2-4 | 15 | 6 |
| Mar 30, 1995 | Evening | 1-2-8 | 11 | 2 |
| Mar 29, 1995 | Evening | 1-1-0 | 2 | 2 |
| Mar 28, 1995 | Evening | 7-1-3 | 11 | 2 |
| Mar 27, 1995 | Evening | 6-7-4 | 17 | 8 |
| Mar 26, 1995 | Evening | 4-9-0 | 13 | 4 |
| Mar 25, 1995 | Evening | 4-3-7 | 14 | 5 |