The winning New York Numbers numbers for October 18, 1993 were: evening 0-5-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 18, 1993 | Evening | 0-5-2 | 7 | 7 |
| Oct 17, 1993 | Evening | 2-5-8 | 15 | 6 |
| Oct 16, 1993 | Evening | 5-1-0 | 6 | 6 |
| Oct 15, 1993 | Evening | 0-9-4 | 13 | 4 |
| Oct 14, 1993 | Evening | 9-3-7 | 19 | 1 |
| Oct 13, 1993 | Evening | 4-5-1 | 10 | 1 |
| Oct 12, 1993 | Evening | 1-1-1 | 3 | 3 |