The winning New York Numbers numbers for September 25, 1993 were: evening 7-7-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 25, 1993 | Evening | 7-7-2 | 16 | 7 |
| Sep 24, 1993 | Evening | 0-6-3 | 9 | 9 |
| Sep 23, 1993 | Evening | 4-9-3 | 16 | 7 |
| Sep 22, 1993 | Evening | 7-2-7 | 16 | 7 |
| Sep 21, 1993 | Evening | 4-5-1 | 10 | 1 |
| Sep 20, 1993 | Evening | 4-6-6 | 16 | 7 |
| Sep 19, 1993 | Evening | 2-4-9 | 15 | 6 |