The winning New York Numbers numbers for September 19, 1993 were: evening 2-4-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 19, 1993 | Evening | 2-4-9 | 15 | 6 |
| Sep 18, 1993 | Evening | 2-2-1 | 5 | 5 |
| Sep 17, 1993 | Evening | 1-1-3 | 5 | 5 |
| Sep 16, 1993 | Evening | 6-9-8 | 23 | 5 |
| Sep 15, 1993 | Evening | 9-5-8 | 22 | 4 |
| Sep 14, 1993 | Evening | 8-0-7 | 15 | 6 |
| Sep 13, 1993 | Evening | 6-1-1 | 8 | 8 |