The winning New York Numbers numbers for August 27, 1993 were: evening 8-2-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 27, 1993 | Evening | 8-2-4 | 14 | 5 |
| Aug 26, 1993 | Evening | 0-2-4 | 6 | 6 |
| Aug 25, 1993 | Evening | 9-6-0 | 15 | 6 |
| Aug 24, 1993 | Evening | 2-6-2 | 10 | 1 |
| Aug 23, 1993 | Evening | 3-1-4 | 8 | 8 |
| Aug 22, 1993 | Evening | 8-8-5 | 21 | 3 |
| Aug 21, 1993 | Evening | 8-3-1 | 12 | 3 |