The winning New York Numbers numbers for August 5, 1993 were: evening 4-7-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Aug 5, 1993 | Evening | 4-7-0 | 11 | 2 |
| Aug 4, 1993 | Evening | 2-1-6 | 9 | 9 |
| Aug 3, 1993 | Evening | 5-8-5 | 18 | 9 |
| Aug 2, 1993 | Evening | 7-8-7 | 22 | 4 |
| Aug 1, 1993 | Evening | 7-5-2 | 14 | 5 |
| Jul 31, 1993 | Evening | 3-4-5 | 12 | 3 |
| Jul 30, 1993 | Evening | 6-3-2 | 11 | 2 |