The winning New York Numbers numbers for July 26, 1993 were: evening 5-3-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 26, 1993 | Evening | 5-3-0 | 8 | 8 |
| Jul 25, 1993 | Evening | 5-6-6 | 17 | 8 |
| Jul 24, 1993 | Evening | 3-1-1 | 5 | 5 |
| Jul 23, 1993 | Evening | 4-0-5 | 9 | 9 |
| Jul 22, 1993 | Evening | 9-9-5 | 23 | 5 |
| Jul 21, 1993 | Evening | 6-4-3 | 13 | 4 |
| Jul 20, 1993 | Evening | 3-9-6 | 18 | 9 |