The winning New York Numbers numbers for April 17, 1993 were: evening 9-3-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Apr 17, 1993 | Evening | 9-3-2 | 14 | 5 |
| Apr 16, 1993 | Evening | 6-6-4 | 16 | 7 |
| Apr 15, 1993 | Evening | 0-9-8 | 17 | 8 |
| Apr 14, 1993 | Evening | 2-1-1 | 4 | 4 |
| Apr 13, 1993 | Evening | 0-2-3 | 5 | 5 |
| Apr 12, 1993 | Evening | 3-1-4 | 8 | 8 |
| Apr 11, 1993 | Evening | 2-5-7 | 14 | 5 |