The winning New York Numbers numbers for December 21, 1991 were: evening 9-2-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 21, 1991 | Evening | 9-2-5 | 16 | 7 |
| Dec 20, 1991 | Evening | 2-2-4 | 8 | 8 |
| Dec 19, 1991 | Evening | 6-0-0 | 6 | 6 |
| Dec 18, 1991 | Evening | 8-6-0 | 14 | 5 |
| Dec 17, 1991 | Evening | 8-9-4 | 21 | 3 |
| Dec 16, 1991 | Evening | 7-7-7 | 21 | 3 |
| Dec 15, 1991 | Evening | 6-4-9 | 19 | 1 |