The winning New York Numbers numbers for October 4, 1991 were: evening 0-6-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 4, 1991 | Evening | 0-6-6 | 12 | 3 |
| Oct 3, 1991 | Evening | 5-7-7 | 19 | 1 |
| Oct 2, 1991 | Evening | 5-5-2 | 12 | 3 |
| Oct 1, 1991 | Evening | 6-3-9 | 18 | 9 |
| Sep 30, 1991 | Evening | 3-0-6 | 9 | 9 |
| Sep 29, 1991 | Evening | 9-7-3 | 19 | 1 |
| Sep 28, 1991 | Evening | 5-6-4 | 15 | 6 |