The winning New York Numbers numbers for March 28, 1991 were: evening 9-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 28, 1991 | Evening | 9-0-0 | 9 | 9 |
| Mar 27, 1991 | Evening | 0-8-8 | 16 | 7 |
| Mar 26, 1991 | Evening | 5-5-9 | 19 | 1 |
| Mar 25, 1991 | Evening | 0-8-6 | 14 | 5 |
| Mar 24, 1991 | Evening | 3-3-2 | 8 | 8 |
| Mar 23, 1991 | Evening | 2-7-5 | 14 | 5 |
| Mar 22, 1991 | Evening | 9-0-9 | 18 | 9 |