The winning New York Numbers numbers for November 25, 1990 were: evening 0-5-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 25, 1990 | Evening | 0-5-4 | 9 | 9 |
| Nov 24, 1990 | Evening | 9-8-3 | 20 | 2 |
| Nov 23, 1990 | Evening | 0-0-6 | 6 | 6 |
| Nov 22, 1990 | Evening | 0-9-5 | 14 | 5 |
| Nov 21, 1990 | Evening | 3-0-6 | 9 | 9 |
| Nov 20, 1990 | Evening | 0-9-5 | 14 | 5 |
| Nov 19, 1990 | Evening | 3-8-5 | 16 | 7 |