The winning New York Numbers numbers for October 3, 1990 were: evening 3-1-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 3, 1990 | Evening | 3-1-0 | 4 | 4 |
| Oct 2, 1990 | Evening | 7-1-0 | 8 | 8 |
| Oct 1, 1990 | Evening | 4-4-1 | 9 | 9 |
| Sep 30, 1990 | Evening | 0-5-0 | 5 | 5 |
| Sep 29, 1990 | Evening | 9-5-1 | 15 | 6 |
| Sep 28, 1990 | Evening | 2-4-0 | 6 | 6 |
| Sep 27, 1990 | Evening | 6-6-4 | 16 | 7 |