The winning New York Numbers numbers for September 11, 1990 were: evening 5-2-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 11, 1990 | Evening | 5-2-2 | 9 | 9 |
| Sep 10, 1990 | Evening | 8-1-8 | 17 | 8 |
| Sep 9, 1990 | Evening | 5-3-7 | 15 | 6 |
| Sep 8, 1990 | Evening | 0-1-8 | 9 | 9 |
| Sep 7, 1990 | Evening | 7-6-1 | 14 | 5 |
| Sep 6, 1990 | Evening | 2-9-3 | 14 | 5 |
| Sep 5, 1990 | Evening | 9-6-6 | 21 | 3 |