The winning New York Numbers numbers for December 31, 1989 were: evening 0-1-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 31, 1989 | Evening | 0-1-4 | 5 | 5 |
| Dec 30, 1989 | Evening | 3-8-1 | 12 | 3 |
| Dec 29, 1989 | Evening | 9-6-8 | 23 | 5 |
| Dec 28, 1989 | Evening | 3-5-7 | 15 | 6 |
| Dec 27, 1989 | Evening | 0-2-2 | 4 | 4 |
| Dec 26, 1989 | Evening | 2-5-9 | 16 | 7 |