The winning New York Numbers numbers for December 9, 1989 were: evening 2-0-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 9, 1989 | Evening | 2-0-1 | 3 | 3 |
| Dec 8, 1989 | Evening | 4-1-3 | 8 | 8 |
| Dec 7, 1989 | Evening | 5-7-1 | 13 | 4 |
| Dec 6, 1989 | Evening | 2-7-6 | 15 | 6 |
| Dec 5, 1989 | Evening | 0-9-6 | 15 | 6 |
| Dec 4, 1989 | Evening | 4-2-2 | 8 | 8 |
| Dec 3, 1989 | Evening | 5-3-6 | 14 | 5 |