The winning New York Numbers numbers for December 3, 1989 were: evening 5-3-6.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 3, 1989 | Evening | 5-3-6 | 14 | 5 |
| Dec 2, 1989 | Evening | 6-5-0 | 11 | 2 |
| Dec 1, 1989 | Evening | 7-1-1 | 9 | 9 |
| Nov 30, 1989 | Evening | 5-1-3 | 9 | 9 |
| Nov 29, 1989 | Evening | 9-6-2 | 17 | 8 |
| Nov 28, 1989 | Evening | 0-1-5 | 6 | 6 |
| Nov 27, 1989 | Evening | 7-1-1 | 9 | 9 |