The winning New York Numbers numbers for November 6, 1989 were: evening 0-0-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 6, 1989 | Evening | 0-0-0 | 0 | 0 |
| Nov 5, 1989 | Evening | 0-5-0 | 5 | 5 |
| Nov 4, 1989 | Evening | 4-6-3 | 13 | 4 |
| Nov 3, 1989 | Evening | 7-3-2 | 12 | 3 |
| Nov 2, 1989 | Evening | 5-0-7 | 12 | 3 |
| Nov 1, 1989 | Evening | 5-7-4 | 16 | 7 |
| Oct 31, 1989 | Evening | 0-6-9 | 15 | 6 |