The winning New York Numbers numbers for October 24, 1989 were: evening 3-4-1.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 24, 1989 | Evening | 3-4-1 | 8 | 8 |
| Oct 23, 1989 | Evening | 4-5-0 | 9 | 9 |
| Oct 22, 1989 | Evening | 8-3-5 | 16 | 7 |
| Oct 21, 1989 | Evening | 0-4-7 | 11 | 2 |
| Oct 20, 1989 | Evening | 9-3-9 | 21 | 3 |
| Oct 19, 1989 | Evening | 0-7-5 | 12 | 3 |
| Oct 18, 1989 | Evening | 9-5-0 | 14 | 5 |