The winning New York Numbers numbers for October 2, 1989 were: evening 3-9-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 2, 1989 | Evening | 3-9-5 | 17 | 8 |
| Oct 1, 1989 | Evening | 6-3-2 | 11 | 2 |
| Sep 30, 1989 | Evening | 5-2-7 | 14 | 5 |
| Sep 29, 1989 | Evening | 9-0-3 | 12 | 3 |
| Sep 28, 1989 | Evening | 0-5-0 | 5 | 5 |
| Sep 27, 1989 | Evening | 5-9-5 | 19 | 1 |
| Sep 26, 1989 | Evening | 6-9-1 | 16 | 7 |