The winning New York Numbers numbers for March 2, 1989 were: evening 1-6-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Mar 2, 1989 | Evening | 1-6-0 | 7 | 7 |
| Mar 1, 1989 | Evening | 2-4-6 | 12 | 3 |
| Feb 28, 1989 | Evening | 9-5-0 | 14 | 5 |
| Feb 27, 1989 | Evening | 7-3-9 | 19 | 1 |
| Feb 26, 1989 | Evening | 5-8-0 | 13 | 4 |
| Feb 25, 1989 | Evening | 7-4-6 | 17 | 8 |
| Feb 24, 1989 | Evening | 1-3-9 | 13 | 4 |