The winning New York Numbers numbers for December 28, 1986 were: evening 3-6-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 28, 1986 | Evening | 3-6-2 | 11 | 2 |
| Dec 27, 1986 | Evening | 7-8-6 | 21 | 3 |
| Dec 26, 1986 | Evening | 7-2-9 | 18 | 9 |
| Dec 24, 1986 | Evening | 1-7-1 | 9 | 9 |
| Dec 23, 1986 | Evening | 3-8-3 | 14 | 5 |
| Dec 22, 1986 | Evening | 3-9-0 | 12 | 3 |