The winning New York Numbers numbers for November 2, 1986 were: evening 1-8-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 2, 1986 | Evening | 1-8-0 | 9 | 9 |
| Nov 1, 1986 | Evening | 4-5-1 | 10 | 1 |
| Oct 31, 1986 | Evening | 1-8-7 | 16 | 7 |
| Oct 30, 1986 | Evening | 7-8-1 | 16 | 7 |
| Oct 29, 1986 | Evening | 0-7-1 | 8 | 8 |
| Oct 28, 1986 | Evening | 9-9-2 | 20 | 2 |
| Oct 27, 1986 | Evening | 4-3-0 | 7 | 7 |