The winning New York Numbers numbers for December 5, 1983 were: evening 8-5-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 5, 1983 | Evening | 8-5-4 | 17 | 8 |
| Dec 4, 1983 | Evening | 8-4-6 | 18 | 9 |
| Dec 3, 1983 | Evening | 4-0-7 | 11 | 2 |
| Dec 2, 1983 | Evening | 7-9-7 | 23 | 5 |
| Dec 1, 1983 | Evening | 2-0-0 | 2 | 2 |
| Nov 30, 1983 | Evening | 0-8-7 | 15 | 6 |
| Nov 29, 1983 | Evening | 7-7-2 | 16 | 7 |