The winning New York Numbers numbers for November 4, 1983 were: evening 7-2-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 4, 1983 | Evening | 7-2-3 | 12 | 3 |
| Nov 3, 1983 | Evening | 8-2-9 | 19 | 1 |
| Nov 2, 1983 | Evening | 9-5-6 | 20 | 2 |
| Nov 1, 1983 | Evening | 0-1-0 | 1 | 1 |
| Oct 31, 1983 | Evening | 6-6-5 | 17 | 8 |
| Oct 30, 1983 | Evening | 9-0-0 | 9 | 9 |
| Oct 29, 1983 | Evening | 4-8-0 | 12 | 3 |