The winning New York Numbers numbers for July 12, 1983 were: evening 4-0-4.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Jul 12, 1983 | Evening | 4-0-4 | 8 | 8 |
| Jul 11, 1983 | Evening | 0-3-5 | 8 | 8 |
| Jul 10, 1983 | Evening | 3-9-6 | 18 | 9 |
| Jul 9, 1983 | Evening | 7-3-9 | 19 | 1 |
| Jul 8, 1983 | Evening | 7-5-8 | 20 | 2 |
| Jul 7, 1983 | Evening | 1-8-5 | 14 | 5 |
| Jul 6, 1983 | Evening | 2-9-4 | 15 | 6 |