The winning Delaware Play 4 numbers for December 21, 2003 were: night 0-7-7-9.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 21, 2003 | Night | 0-7-7-9 | 23 | 5 |
| Dec 20, 2003 | Night | 3-8-5-5 | 21 | 3 |
| Dec 20, 2003 | Day | 1-8-5-0 | 14 | 5 |
| Dec 19, 2003 | Night | 6-3-8-8 | 25 | 7 |
| Dec 19, 2003 | Day | 7-6-8-1 | 22 | 4 |
| Dec 18, 2003 | Night | 7-4-9-8 | 28 | 1 |
| Dec 18, 2003 | Day | 5-3-5-9 | 22 | 4 |
| Dec 17, 2003 | Night | 6-5-2-9 | 22 | 4 |
| Dec 17, 2003 | Day | 8-9-9-8 | 34 | 7 |
| Dec 16, 2003 | Night | 8-0-2-3 | 13 | 4 |
| Dec 16, 2003 | Day | 0-2-4-0 | 6 | 6 |
| Dec 15, 2003 | Night | 8-8-4-4 | 24 | 6 |
| Dec 15, 2003 | Day | 6-9-6-4 | 25 | 7 |