The winning Delaware Play 4 numbers for December 16, 2003 were: day 0-2-4-0; night 8-0-2-3.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Dec 16, 2003 | Night | 8-0-2-3 | 13 | 4 |
| Dec 16, 2003 | Day | 0-2-4-0 | 6 | 6 |
| Dec 15, 2003 | Night | 8-8-4-4 | 24 | 6 |
| Dec 15, 2003 | Day | 6-9-6-4 | 25 | 7 |
| Dec 14, 2003 | Night | 4-4-6-1 | 15 | 6 |
| Dec 13, 2003 | Night | 8-4-8-0 | 20 | 2 |
| Dec 13, 2003 | Day | 3-3-8-7 | 21 | 3 |
| Dec 12, 2003 | Night | 3-3-0-4 | 10 | 1 |
| Dec 12, 2003 | Day | 1-9-6-0 | 16 | 7 |
| Dec 11, 2003 | Night | 4-2-3-6 | 15 | 6 |
| Dec 11, 2003 | Day | 0-4-3-7 | 14 | 5 |
| Dec 10, 2003 | Night | 7-4-9-0 | 20 | 2 |
| Dec 10, 2003 | Day | 8-0-7-7 | 22 | 4 |