The winning Delaware Play 4 numbers for November 30, 2003 were: night 0-0-2-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 30, 2003 | Night | 0-0-2-5 | 7 | 7 |
| Nov 29, 2003 | Night | 0-1-0-7 | 8 | 8 |
| Nov 29, 2003 | Day | 5-8-1-6 | 20 | 2 |
| Nov 28, 2003 | Night | 8-4-2-7 | 21 | 3 |
| Nov 28, 2003 | Day | 7-1-5-2 | 15 | 6 |
| Nov 27, 2003 | Night | 0-9-7-0 | 16 | 7 |
| Nov 27, 2003 | Day | 0-0-9-2 | 11 | 2 |
| Nov 26, 2003 | Night | 5-7-9-8 | 29 | 2 |
| Nov 26, 2003 | Day | 7-4-5-4 | 20 | 2 |
| Nov 25, 2003 | Night | 0-2-1-2 | 5 | 5 |
| Nov 25, 2003 | Day | 7-8-9-7 | 31 | 4 |
| Nov 24, 2003 | Night | 3-7-8-6 | 24 | 6 |
| Nov 24, 2003 | Day | 4-4-6-4 | 18 | 9 |