The winning Delaware Play 4 numbers for November 23, 2003 were: night 5-8-0-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 23, 2003 | Night | 5-8-0-7 | 20 | 2 |
| Nov 22, 2003 | Night | 8-7-9-2 | 26 | 8 |
| Nov 22, 2003 | Day | 4-2-8-0 | 14 | 5 |
| Nov 21, 2003 | Night | 6-8-8-9 | 31 | 4 |
| Nov 21, 2003 | Day | 1-1-2-1 | 5 | 5 |
| Nov 20, 2003 | Night | 5-8-8-8 | 29 | 2 |
| Nov 20, 2003 | Day | 8-1-8-0 | 17 | 8 |
| Nov 19, 2003 | Night | 3-2-4-2 | 11 | 2 |
| Nov 19, 2003 | Day | 9-4-4-8 | 25 | 7 |
| Nov 18, 2003 | Night | 6-5-3-5 | 19 | 1 |
| Nov 18, 2003 | Day | 2-7-0-5 | 14 | 5 |
| Nov 17, 2003 | Night | 6-8-3-8 | 25 | 7 |
| Nov 17, 2003 | Day | 7-2-5-4 | 18 | 9 |