The winning Delaware Play 4 numbers for November 16, 2003 were: night 9-1-7-5.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Nov 16, 2003 | Night | 9-1-7-5 | 22 | 4 |
| Nov 15, 2003 | Night | 2-7-0-5 | 14 | 5 |
| Nov 15, 2003 | Day | 5-5-3-5 | 18 | 9 |
| Nov 14, 2003 | Night | 5-1-8-6 | 20 | 2 |
| Nov 14, 2003 | Day | 0-8-3-2 | 13 | 4 |
| Nov 13, 2003 | Night | 7-3-1-3 | 14 | 5 |
| Nov 13, 2003 | Day | 2-3-6-8 | 19 | 1 |
| Nov 12, 2003 | Night | 4-6-5-0 | 15 | 6 |
| Nov 12, 2003 | Day | 1-9-3-1 | 14 | 5 |
| Nov 11, 2003 | Night | 1-9-8-2 | 20 | 2 |
| Nov 11, 2003 | Day | 6-4-2-8 | 20 | 2 |
| Nov 10, 2003 | Night | 6-3-8-2 | 19 | 1 |
| Nov 10, 2003 | Day | 4-4-2-1 | 11 | 2 |