The winning Delaware Play 4 numbers for October 12, 2003 were: night 3-3-9-0.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Oct 12, 2003 | Night | 3-3-9-0 | 15 | 6 |
| Oct 11, 2003 | Night | 5-8-1-4 | 18 | 9 |
| Oct 11, 2003 | Day | 7-5-5-8 | 25 | 7 |
| Oct 10, 2003 | Night | 3-9-7-8 | 27 | 9 |
| Oct 10, 2003 | Day | 0-7-9-2 | 18 | 9 |
| Oct 9, 2003 | Night | 3-7-7-5 | 22 | 4 |
| Oct 9, 2003 | Day | 6-4-3-8 | 21 | 3 |
| Oct 8, 2003 | Night | 7-2-4-3 | 16 | 7 |
| Oct 8, 2003 | Day | 1-9-0-3 | 13 | 4 |
| Oct 7, 2003 | Night | 6-5-4-0 | 15 | 6 |
| Oct 7, 2003 | Day | 9-5-5-7 | 26 | 8 |
| Oct 6, 2003 | Night | 2-8-8-2 | 20 | 2 |
| Oct 6, 2003 | Day | 9-0-2-2 | 13 | 4 |