The winning Delaware Play 4 numbers for September 19, 2003 were: day 9-6-6-7; night 4-4-4-7.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 19, 2003 | Night | 4-4-4-7 | 19 | 1 |
| Sep 19, 2003 | Day | 9-6-6-7 | 28 | 1 |
| Sep 18, 2003 | Night | 0-3-5-8 | 16 | 7 |
| Sep 18, 2003 | Day | 5-0-3-1 | 9 | 9 |
| Sep 17, 2003 | Night | 4-9-9-4 | 26 | 8 |
| Sep 17, 2003 | Day | 5-8-7-2 | 22 | 4 |
| Sep 16, 2003 | Night | 2-2-5-2 | 11 | 2 |
| Sep 16, 2003 | Day | 7-3-4-6 | 20 | 2 |
| Sep 15, 2003 | Night | 5-8-3-0 | 16 | 7 |
| Sep 15, 2003 | Day | 7-2-2-3 | 14 | 5 |
| Sep 14, 2003 | Night | 6-5-0-3 | 14 | 5 |
| Sep 13, 2003 | Night | 7-7-0-2 | 16 | 7 |
| Sep 13, 2003 | Day | 6-6-9-3 | 24 | 6 |