The winning Delaware Play 4 numbers for September 12, 2003 were: day 1-6-5-3; night 4-0-5-2.
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
Sum is the digits added together (5+5+0 = 10). Root sum keeps adding until one digit is left (10 → 1+0 = 1) — many regular players track it in their notebooks. Odd/Even marks each digit O or E (5-5-0 = OOE). High/Low marks 0–4 as L and 5–9 as H (5-5-0 = HHL).
| Date | Draw | Numbers | Sum | Root |
|---|---|---|---|---|
| Sep 12, 2003 | Night | 4-0-5-2 | 11 | 2 |
| Sep 12, 2003 | Day | 1-6-5-3 | 15 | 6 |
| Sep 11, 2003 | Night | 8-2-8-4 | 22 | 4 |
| Sep 11, 2003 | Day | 8-0-1-8 | 17 | 8 |
| Sep 10, 2003 | Night | 4-6-6-5 | 21 | 3 |
| Sep 10, 2003 | Day | 9-4-1-0 | 14 | 5 |
| Sep 9, 2003 | Night | 0-3-0-9 | 12 | 3 |
| Sep 9, 2003 | Day | 3-2-1-8 | 14 | 5 |
| Sep 8, 2003 | Night | 9-2-4-0 | 15 | 6 |
| Sep 8, 2003 | Day | 9-9-7-3 | 28 | 1 |
| Sep 7, 2003 | Night | 6-2-6-1 | 15 | 6 |
| Sep 6, 2003 | Night | 3-1-7-6 | 17 | 8 |
| Sep 6, 2003 | Day | 3-0-0-0 | 3 | 3 |